Base | Representation |
---|---|
bin | 10011001101011000010… |
… | …011000011110100110001 |
3 | 11200012020121021120001122 |
4 | 103031120103003310301 |
5 | 133111413301220111 |
6 | 2450225532112025 |
7 | 164240505565604 |
oct | 23153023036461 |
9 | 4605217246048 |
10 | 1320036351281 |
11 | 46990811a49a |
12 | 1939b9605615 |
13 | 9762c18bbbb |
14 | 47c6661433b |
15 | 2450ce71cdb |
hex | 133584c3d31 |
1320036351281 has 2 divisors, whose sum is σ = 1320036351282. Its totient is φ = 1320036351280.
The previous prime is 1320036351229. The next prime is 1320036351299. The reversal of 1320036351281 is 1821536300231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1256136600625 + 63899750656 = 1120775^2 + 252784^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320036351281 is a prime.
It is a super-2 number, since 2×13200363512812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1320036321281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660018175640 + 660018175641.
It is an arithmetic number, because the mean of its divisors is an integer number (660018175641).
Almost surely, 21320036351281 is an apocalyptic number.
It is an amenable number.
1320036351281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320036351281 is an equidigital number, since it uses as much as digits as its factorization.
1320036351281 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 1320036351281 in words is "one trillion, three hundred twenty billion, thirty-six million, three hundred fifty-one thousand, two hundred eighty-one".
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