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1320100220211 = 3440033406737
BaseRepresentation
bin10011001101011100000…
…110101100110100110011
311200012102001110102202120
4103031130012230310303
5133112031124021321
62450240133045323
7164242212505443
oct23153406546463
94605361412676
101320100220211
11469940183133
12193a16a86843
139763c491b76
1447c70cbc123
152451388aec6
hex1335c1acd33

1320100220211 has 4 divisors (see below), whose sum is σ = 1760133626952. Its totient is φ = 880066813472.

The previous prime is 1320100220209. The next prime is 1320100220233. The reversal of 1320100220211 is 1120220010231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1320100220211 - 21 = 1320100220209 is a prime.

It is a super-2 number, since 2×13201002202112 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1320100220291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220016703366 + ... + 220016703371.

It is an arithmetic number, because the mean of its divisors is an integer number (440033406738).

Almost surely, 21320100220211 is an apocalyptic number.

1320100220211 is a deficient number, since it is larger than the sum of its proper divisors (440033406741).

1320100220211 is an equidigital number, since it uses as much as digits as its factorization.

1320100220211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440033406740.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1320100220211 its reverse (1120220010231), we get a palindrome (2440320230442).

The spelling of 1320100220211 in words is "one trillion, three hundred twenty billion, one hundred million, two hundred twenty thousand, two hundred eleven".

Divisors: 1 3 440033406737 1320100220211