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13201102003147 is a prime number
BaseRepresentation
bin1100000000011001111011…
…1111101101101111001011
31201202000100111101202220021
43000012132333231233023
53212241324103100042
644024300314241311
72531514420413512
oct300063677555713
951660314352807
1013201102003147
11422a612a241a3
121592566426237
13749b213a9c56
14338d18607679
1517d5ce73a867
hexc019efedbcb

13201102003147 has 2 divisors, whose sum is σ = 13201102003148. Its totient is φ = 13201102003146.

The previous prime is 13201102003109. The next prime is 13201102003169. The reversal of 13201102003147 is 74130020110231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13201102003147 - 235 = 13166742264779 is a prime.

It is not a weakly prime, because it can be changed into another prime (13201102003547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600551001573 + 6600551001574.

It is an arithmetic number, because the mean of its divisors is an integer number (6600551001574).

Almost surely, 213201102003147 is an apocalyptic number.

13201102003147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201102003147 is an equidigital number, since it uses as much as digits as its factorization.

13201102003147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 13201102003147 its reverse (74130020110231), we get a palindrome (87331122113378).

The spelling of 13201102003147 in words is "thirteen trillion, two hundred one billion, one hundred two million, three thousand, one hundred forty-seven".