Base | Representation |
---|---|
bin | 111101011110010001… |
… | …0000001111101111011 |
3 | 110121202010222022011211 |
4 | 1322330202001331323 |
5 | 4130330041301233 |
6 | 140351232303551 |
7 | 12352244652061 |
oct | 1727442017573 |
9 | 417663868154 |
10 | 132012056443 |
11 | 50a934009a3 |
12 | 217026a1bb7 |
13 | c5aa9b0787 |
14 | 65647c2031 |
15 | 36798085cd |
hex | 1ebc881f7b |
132012056443 has 2 divisors, whose sum is σ = 132012056444. Its totient is φ = 132012056442.
The previous prime is 132012056413. The next prime is 132012056489. The reversal of 132012056443 is 344650210231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132012056443 is a prime.
It is not a weakly prime, because it can be changed into another prime (132012056413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006028221 + 66006028222.
It is an arithmetic number, because the mean of its divisors is an integer number (66006028222).
Almost surely, 2132012056443 is an apocalyptic number.
132012056443 is a deficient number, since it is larger than the sum of its proper divisors (1).
132012056443 is an equidigital number, since it uses as much as digits as its factorization.
132012056443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 132012056443 its reverse (344650210231), we get a palindrome (476662266674).
The spelling of 132012056443 in words is "one hundred thirty-two billion, twelve million, fifty-six thousand, four hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •