132012213111331 has 4 divisors (see below), whose sum is σ = 150871100698672. Its totient is φ = 113153325523992.

The previous prime is 132012213111293. The next prime is 132012213111341. The reversal of 132012213111331 is 133111312210231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132012213111331 is a prime.

It is a super-2 number, since 2×132012213111331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132012213111296 and 132012213111305.

It is not an unprimeable number, because it can be changed into a prime (132012213111341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9429443793660 + ... + 9429443793673.

It is an arithmetic number, because the mean of its divisors is an integer number (37717775174668).

Almost surely, 2^{132012213111331} is an apocalyptic number.

132012213111331 is a deficient number, since it is larger than the sum of its proper divisors (18858887587341).

132012213111331 is an equidigital number, since it uses as much as digits as its factorization.

132012213111331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18858887587340.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 132012213111331 its reverse (133111312210231), we get a palindrome (265123525321562).

The spelling of 132012213111331 in words is "one hundred thirty-two trillion, twelve billion, two hundred thirteen million, one hundred eleven thousand, three hundred thirty-one".