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13201231520050 = 25271946110913947
BaseRepresentation
bin1100000000011010011010…
…1101110010000100110010
31201202000200112002220200121
43000012212231302010302
53212242110232120200
644024321222240454
72531520552323020
oct300064655620462
951660615086617
1013201231520050
11422a67a046162
1215925a188612a
13749b42186882
14338d2b8bd710
1517d5dacc0e1a
hexc01a6b72132

13201231520050 has 192 divisors, whose sum is σ = 29637713064960. Its totient is φ = 4273612704000.

The previous prime is 13201231520011. The next prime is 13201231520051. The reversal of 13201231520050 is 5002513210231.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a junction number, because it is equal to n+sod(n) for n = 13201231519997 and 13201231520024.

It is not an unprimeable number, because it can be changed into a prime (13201231520051) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3344622177 + ... + 3344626123.

It is an arithmetic number, because the mean of its divisors is an integer number (154363088880).

Almost surely, 213201231520050 is an apocalyptic number.

13201231520050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13201231520050 is an abundant number, since it is smaller than the sum of its proper divisors (16436481544910).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13201231520050 is a wasteful number, since it uses less digits than its factorization.

13201231520050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5537 (or 5532 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 13201231520050 its reverse (5002513210231), we get a palindrome (18203744730281).

The spelling of 13201231520050 in words is "thirteen trillion, two hundred one billion, two hundred thirty-one million, five hundred twenty thousand, fifty".