Base | Representation |
---|---|
bin | 1100000000011010011010… |
… | …1101110010000101010011 |
3 | 1201202000200112002220201211 |
4 | 3000012212231302011103 |
5 | 3212242110232120313 |
6 | 44024321222240551 |
7 | 2531520552323065 |
oct | 300064655620523 |
9 | 51660615086654 |
10 | 13201231520083 |
11 | 422a67a046192 |
12 | 15925a1886157 |
13 | 749b421868a9 |
14 | 338d2b8bd735 |
15 | 17d5dacc0e3d |
hex | c01a6b72153 |
13201231520083 has 2 divisors, whose sum is σ = 13201231520084. Its totient is φ = 13201231520082.
The previous prime is 13201231520051. The next prime is 13201231520111. The reversal of 13201231520083 is 38002513210231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13201231520083 - 25 = 13201231520051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13201231520683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600615760041 + 6600615760042.
It is an arithmetic number, because the mean of its divisors is an integer number (6600615760042).
Almost surely, 213201231520083 is an apocalyptic number.
13201231520083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201231520083 is an equidigital number, since it uses as much as digits as its factorization.
13201231520083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 13201231520083 in words is "thirteen trillion, two hundred one billion, two hundred thirty-one million, five hundred twenty thousand, eighty-three".
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