Base | Representation |
---|---|
bin | 10011001101011101100… |
… | …110110000101111000011 |
3 | 11200012110210211210202022 |
4 | 103031131212300233003 |
5 | 133112104100331201 |
6 | 2450242432512055 |
7 | 164242636526051 |
oct | 23153546605703 |
9 | 4605423753668 |
10 | 1320125402051 |
11 | 469953412675 |
12 | 193a233ab62b |
13 | 9764476aa71 |
14 | 47c743951d1 |
15 | 24515bb241b |
hex | 1335d9b0bc3 |
1320125402051 has 4 divisors (see below), whose sum is σ = 1320171490704. Its totient is φ = 1320079313400.
The previous prime is 1320125402027. The next prime is 1320125402069. The reversal of 1320125402051 is 1502045210231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320125402051 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1320125402051.
It is not an unprimeable number, because it can be changed into a prime (1320125402851) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23001335 + ... + 23058656.
It is an arithmetic number, because the mean of its divisors is an integer number (330042872676).
Almost surely, 21320125402051 is an apocalyptic number.
1320125402051 is a deficient number, since it is larger than the sum of its proper divisors (46088653).
1320125402051 is an equidigital number, since it uses as much as digits as its factorization.
1320125402051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46088652.
The product of its (nonzero) digits is 2400, while the sum is 26.
The spelling of 1320125402051 in words is "one trillion, three hundred twenty billion, one hundred twenty-five million, four hundred two thousand, fifty-one".
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