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1320130353 = 3440043451
BaseRepresentation
bin100111010101111…
…1001011100110001
310102000001120101210
41032223321130301
510200423132403
6334554550333
744466631353
oct11653713461
93360046353
101320130353
116181a7523
1230a1383a9
13180665829
14c74810d3
157ad69b03
hex4eaf9731

1320130353 has 4 divisors (see below), whose sum is σ = 1760173808. Its totient is φ = 880086900.

The previous prime is 1320130351. The next prime is 1320130387. The reversal of 1320130353 is 3530310231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1320130353 - 21 = 1320130351 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1320130351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220021723 + ... + 220021728.

It is an arithmetic number, because the mean of its divisors is an integer number (440043452).

Almost surely, 21320130353 is an apocalyptic number.

It is an amenable number.

1320130353 is a deficient number, since it is larger than the sum of its proper divisors (440043455).

1320130353 is an equidigital number, since it uses as much as digits as its factorization.

1320130353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440043454.

The product of its (nonzero) digits is 810, while the sum is 21.

The square root of 1320130353 is about 36333.5981290045. The cubic root of 1320130353 is about 1096.9974184388.

Adding to 1320130353 its reverse (3530310231), we get a palindrome (4850440584).

The spelling of 1320130353 in words is "one billion, three hundred twenty million, one hundred thirty thousand, three hundred fifty-three".

Divisors: 1 3 440043451 1320130353