13201311122113 has 4 divisors (see below), whose sum is σ = 13324687861680. Its totient is φ = 13077934382548.

The previous prime is 13201311122099. The next prime is 13201311122149. The reversal of 13201311122113 is 31122111310231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13201311122113 - 2⁵ = 13201311122081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13201311128113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61688369623 + ... + 61688369836.

It is an arithmetic number, because the mean of its divisors is an integer number (3331171965420).

Almost surely, 2^{13201311122113} is an apocalyptic number.

It is an amenable number.

13201311122113 is a deficient number, since it is larger than the sum of its proper divisors (123376739567).

13201311122113 is a wasteful number, since it uses less digits than its factorization.

13201311122113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123376739566.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 13201311122113 its reverse (31122111310231), we get a palindrome (44323422432344).

The spelling of 13201311122113 in words is "thirteen trillion, two hundred one billion, three hundred eleven million, one hundred twenty-two thousand, one hundred thirteen".