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132013212169 is a prime number
BaseRepresentation
bin111101011110010011…
…0011100001000001001
3110121202020011000112111
41322330212130020021
54130330340242134
6140351313142321
712352260534406
oct1727446341011
9417666130474
10132013212169
1150a94020243
1221702b5a9a1
13c5aacc6837
146564a032ad
153679985c64
hex1ebc99c209

132013212169 has 2 divisors, whose sum is σ = 132013212170. Its totient is φ = 132013212168.

The previous prime is 132013212077. The next prime is 132013212179. The reversal of 132013212169 is 961212310231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129951598144 + 2061614025 = 360488^2 + 45405^2 .

It is a cyclic number.

It is not a de Polignac number, because 132013212169 - 215 = 132013179401 is a prime.

It is a super-2 number, since 2×1320132121692 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132013212169.

It is not a weakly prime, because it can be changed into another prime (132013212179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006606084 + 66006606085.

It is an arithmetic number, because the mean of its divisors is an integer number (66006606085).

Almost surely, 2132013212169 is an apocalyptic number.

It is an amenable number.

132013212169 is a deficient number, since it is larger than the sum of its proper divisors (1).

132013212169 is an equidigital number, since it uses as much as digits as its factorization.

132013212169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 132013212169 in words is "one hundred thirty-two billion, thirteen million, two hundred twelve thousand, one hundred sixty-nine".