Base | Representation |
---|---|
bin | 1100000000011010110000… |
… | …1110100111101010000011 |
3 | 1201202000220222011002211021 |
4 | 3000012230032213222003 |
5 | 3212242302421423321 |
6 | 44024334324530311 |
7 | 2531523054444214 |
oct | 300065416475203 |
9 | 51660828132737 |
10 | 13201324014211 |
11 | 422a717280413 |
12 | 1592608850997 |
13 | 749b5839cb48 |
14 | 338d39cb940b |
15 | 17d5e3e91941 |
hex | c01ac3a7a83 |
13201324014211 has 2 divisors, whose sum is σ = 13201324014212. Its totient is φ = 13201324014210.
The previous prime is 13201324014161. The next prime is 13201324014233. The reversal of 13201324014211 is 11241042310231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13201324014211 - 231 = 13199176530563 is a prime.
It is not a weakly prime, because it can be changed into another prime (13201324024211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600662007105 + 6600662007106.
It is an arithmetic number, because the mean of its divisors is an integer number (6600662007106).
Almost surely, 213201324014211 is an apocalyptic number.
13201324014211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201324014211 is an equidigital number, since it uses as much as digits as its factorization.
13201324014211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13201324014211 its reverse (11241042310231), we get a palindrome (24442366324442).
The spelling of 13201324014211 in words is "thirteen trillion, two hundred one billion, three hundred twenty-four million, fourteen thousand, two hundred eleven".
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