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13201324561 = 34738044163
BaseRepresentation
bin11000100101101110…
…00011101000010001
31021002000121202211201
430102313003220101
5204014014341221
610021542111201
7645066256465
oct142267035021
937060552751
1013201324561
115664892597
12268511b501
131325000b69
148d33b44a5
15523e6d891
hex312dc3a11

13201324561 has 4 divisors (see below), whose sum is σ = 13239369072. Its totient is φ = 13163280052.

The previous prime is 13201324547. The next prime is 13201324567. The reversal of 13201324561 is 16542310231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 16542310231 = 53933067367.

It is a cyclic number.

It is not a de Polignac number, because 13201324561 - 215 = 13201291793 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13201324567) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19021735 + ... + 19022428.

It is an arithmetic number, because the mean of its divisors is an integer number (3309842268).

Almost surely, 213201324561 is an apocalyptic number.

It is an amenable number.

13201324561 is a deficient number, since it is larger than the sum of its proper divisors (38044511).

13201324561 is an equidigital number, since it uses as much as digits as its factorization.

13201324561 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38044510.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 13201324561 its reverse (16542310231), we get a palindrome (29743634792).

The spelling of 13201324561 in words is "thirteen billion, two hundred one million, three hundred twenty-four thousand, five hundred sixty-one".

Divisors: 1 347 38044163 13201324561