Base | Representation |
---|---|
bin | 1100000000011010111000… |
… | …0110000111100111010011 |
3 | 1201202001000011002122001200 |
4 | 3000012232012013213103 |
5 | 3212242333431341433 |
6 | 44024341404202243 |
7 | 2531523614634600 |
oct | 300065606074723 |
9 | 51661004078050 |
10 | 13201355340243 |
11 | 422a732a270a4 |
12 | 1592617239383 |
13 | 749b61a1a565 |
14 | 338d401116a7 |
15 | 17d5e6acd613 |
hex | c01ae1879d3 |
13201355340243 has 36 divisors (see below), whose sum is σ = 22600395050688. Its totient is φ = 7401298937760.
The previous prime is 13201355340223. The next prime is 13201355340253. The reversal of 13201355340243 is 34204355310231.
13201355340243 is a `hidden beast` number, since 1 + 3 + 20 + 1 + 3 + 55 + 340 + 243 = 666.
It is not a de Polignac number, because 13201355340243 - 25 = 13201355340211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13201355340198 and 13201355340207.
It is not an unprimeable number, because it can be changed into a prime (13201355340223) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 282382723 + ... + 282429468.
It is an arithmetic number, because the mean of its divisors is an integer number (627788751408).
Almost surely, 213201355340243 is an apocalyptic number.
13201355340243 is a deficient number, since it is larger than the sum of its proper divisors (9399039710445).
13201355340243 is a wasteful number, since it uses less digits than its factorization.
13201355340243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 564812264 (or 564812254 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 36.
The spelling of 13201355340243 in words is "thirteen trillion, two hundred one billion, three hundred fifty-five million, three hundred forty thousand, two hundred forty-three".
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