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132014021000311 = 9713734332893703
BaseRepresentation
bin11110000001000011101000…
…110100111011110001110111
3122022102102021002211202022201
4132001003220310323301313
5114300404203334002221
61144434223133405331
736543461335561462
oct3601035064736167
9568372232752281
10132014021000311
113907791729007a
1212981250639847
135887b3a89bc38
142485726c302d9
15103dec3456891
hex7810e8d3bc77

132014021000311 has 16 divisors (see below), whose sum is σ = 134387711244864. Its totient is φ = 129661554806784.

The previous prime is 132014021000233. The next prime is 132014021000401. The reversal of 132014021000311 is 113000120410231.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132014021000311 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132014021000611) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44174286 + ... + 47067988.

It is an arithmetic number, because the mean of its divisors is an integer number (8399231952804).

Almost surely, 2132014021000311 is an apocalyptic number.

132014021000311 is a deficient number, since it is larger than the sum of its proper divisors (2373690244553).

132014021000311 is a wasteful number, since it uses less digits than its factorization.

132014021000311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2897370.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 132014021000311 its reverse (113000120410231), we get a palindrome (245014141410542).

The spelling of 132014021000311 in words is "one hundred thirty-two trillion, fourteen billion, twenty-one million, three hundred eleven", and thus it is an aban number.

Divisors: 1 97 137 3433 13289 333001 470321 2893703 45621137 280689191 396437311 9934082399 38454419167 963605992703 1360969288663 132014021000311