Base | Representation |
---|---|
bin | 11110000001000011101010… |
… | …110110101000110101100010 |
3 | 122022102102100110211012002212 |
4 | 132001003222312220311202 |
5 | 114300404241040021232 |
6 | 1144434230350242122 |
7 | 36543462230563235 |
oct | 3601035266506542 |
9 | 568372313735085 |
10 | 132014055001442 |
11 | 390779344a3689 |
12 | 1298125bab6342 |
13 | 5887b44945153 |
14 | 248572b56141c |
15 | 103dec6420eb2 |
hex | 7810eada8d62 |
132014055001442 has 4 divisors (see below), whose sum is σ = 198021082502166. Its totient is φ = 66007027500720.
The previous prime is 132014055001391. The next prime is 132014055001453. The reversal of 132014055001442 is 244100550410231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 127796038605481 + 4218016395961 = 11304691^2 + 2053781^2 .
It is a junction number, because it is equal to n+sod(n) for n = 132014055001399 and 132014055001408.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33003513750359 + ... + 33003513750362.
Almost surely, 2132014055001442 is an apocalyptic number.
132014055001442 is a deficient number, since it is larger than the sum of its proper divisors (66007027500724).
132014055001442 is an equidigital number, since it uses as much as digits as its factorization.
132014055001442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66007027500723.
The product of its (nonzero) digits is 19200, while the sum is 32.
The spelling of 132014055001442 in words is "one hundred thirty-two trillion, fourteen billion, fifty-five million, one thousand, four hundred forty-two".
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