Base | Representation |
---|---|
bin | 1100000000011011000111… |
… | …1110001000011000101001 |
3 | 1201202001011200102201200211 |
4 | 3000012301332020120221 |
5 | 3212243002102330423 |
6 | 44024352045501121 |
7 | 2531525334356404 |
oct | 300066176103051 |
9 | 51661150381624 |
10 | 13201420355113 |
11 | 422a7666a27a1 |
12 | 1592634b717a1 |
13 | 749b72331cb3 |
14 | 338d489d6d3b |
15 | 17d5ec67210d |
hex | c01b1f88629 |
13201420355113 has 8 divisors (see below), whose sum is σ = 13424341251456. Its totient is φ = 12978709270800.
The previous prime is 13201420355107. The next prime is 13201420355159. The reversal of 13201420355113 is 31155302410231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13201420355113 - 213 = 13201420346921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13201420325113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52326103 + ... + 52577788.
It is an arithmetic number, because the mean of its divisors is an integer number (1678042656432).
Almost surely, 213201420355113 is an apocalyptic number.
It is an amenable number.
13201420355113 is a deficient number, since it is larger than the sum of its proper divisors (222920896343).
13201420355113 is a wasteful number, since it uses less digits than its factorization.
13201420355113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104906015.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13201420355113 its reverse (31155302410231), we get a palindrome (44356722765344).
The spelling of 13201420355113 in words is "thirteen trillion, two hundred one billion, four hundred twenty million, three hundred fifty-five thousand, one hundred thirteen".
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