Base | Representation |
---|---|
bin | 11110000001000011111111… |
… | …100011111001011000111011 |
3 | 122022102110020200112101010002 |
4 | 132001003333203321120323 |
5 | 114300410444004110133 |
6 | 1144434325040343215 |
7 | 36543503646525266 |
oct | 3601037743713073 |
9 | 568373220471102 |
10 | 132014402410043 |
11 | 39077aa260892a |
12 | 12981338314b0b |
13 | 5887b9b90197a |
14 | 2485761755cdd |
15 | 103dee6b96ce8 |
hex | 7810ff8f963b |
132014402410043 has 2 divisors, whose sum is σ = 132014402410044. Its totient is φ = 132014402410042.
The previous prime is 132014402409973. The next prime is 132014402410049. The reversal of 132014402410043 is 340014204410231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132014402410043 - 28 = 132014402409787 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132014402409988 and 132014402410015.
It is not a weakly prime, because it can be changed into another prime (132014402410049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007201205021 + 66007201205022.
It is an arithmetic number, because the mean of its divisors is an integer number (66007201205022).
Almost surely, 2132014402410043 is an apocalyptic number.
132014402410043 is a deficient number, since it is larger than the sum of its proper divisors (1).
132014402410043 is an equidigital number, since it uses as much as digits as its factorization.
132014402410043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 132014402410043 its reverse (340014204410231), we get a palindrome (472028606820274).
The spelling of 132014402410043 in words is "one hundred thirty-two trillion, fourteen billion, four hundred two million, four hundred ten thousand, forty-three".
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