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132014535531121 is a prime number
BaseRepresentation
bin11110000001000100000111…
…011111101101101001110001
3122022102110120222000121220101
4132001010013133231221301
5114300411232043443441
61144434350153512401
736543510154165345
oct3601040737555161
9568373528017811
10132014535531121
1139078060771751
1212981374a12701
135887bc0370c39
1424857752c9625
15103e0036e0231
hex7811077eda71

132014535531121 has 2 divisors, whose sum is σ = 132014535531122. Its totient is φ = 132014535531120.

The previous prime is 132014535531101. The next prime is 132014535531227. The reversal of 132014535531121 is 121135535410231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104621496256225 + 27393039274896 = 10228465^2 + 5233836^2 .

It is a cyclic number.

It is not a de Polignac number, because 132014535531121 - 29 = 132014535530609 is a prime.

It is not a weakly prime, because it can be changed into another prime (132014535531101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007267765560 + 66007267765561.

It is an arithmetic number, because the mean of its divisors is an integer number (66007267765561).

Almost surely, 2132014535531121 is an apocalyptic number.

It is an amenable number.

132014535531121 is a deficient number, since it is larger than the sum of its proper divisors (1).

132014535531121 is an equidigital number, since it uses as much as digits as its factorization.

132014535531121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 37.

The spelling of 132014535531121 in words is "one hundred thirty-two trillion, fourteen billion, five hundred thirty-five million, five hundred thirty-one thousand, one hundred twenty-one".