Base | Representation |
---|---|
bin | 11110000001000100000111… |
… | …011111101101101011100001 |
3 | 122022102110120222000122001112 |
4 | 132001010013133231223201 |
5 | 114300411232043444413 |
6 | 1144434350153513105 |
7 | 36543510154165565 |
oct | 3601040737555341 |
9 | 568373528018045 |
10 | 132014535531233 |
11 | 39078060771843 |
12 | 12981374a12795 |
13 | 5887bc0370cc4 |
14 | 24857752c96a5 |
15 | 103e0036e02a8 |
hex | 7811077edae1 |
132014535531233 has 4 divisors (see below), whose sum is σ = 132080974655280. Its totient is φ = 131948096407188.
The previous prime is 132014535531227. The next prime is 132014535531299. The reversal of 132014535531233 is 332135535410231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 132014535531233 - 232 = 132010240563937 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132014535731233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33219559043 + ... + 33219563016.
It is an arithmetic number, because the mean of its divisors is an integer number (33020243663820).
Almost surely, 2132014535531233 is an apocalyptic number.
It is an amenable number.
132014535531233 is a deficient number, since it is larger than the sum of its proper divisors (66439124047).
132014535531233 is an equidigital number, since it uses as much as digits as its factorization.
132014535531233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66439124046.
The product of its (nonzero) digits is 486000, while the sum is 41.
The spelling of 132014535531233 in words is "one hundred thirty-two trillion, fourteen billion, five hundred thirty-five million, five hundred thirty-one thousand, two hundred thirty-three".
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