Base | Representation |
---|---|
bin | 11110000001000100000111… |
… | …011111111100010011100011 |
3 | 122022102110120222010200020021 |
4 | 132001010013133330103203 |
5 | 114300411232102404024 |
6 | 1144434350155054311 |
7 | 36543510154535335 |
oct | 3601040737742343 |
9 | 568373528120207 |
10 | 132014535591139 |
11 | 39078060802853 |
12 | 12981374a41397 |
13 | 5887bc0392356 |
14 | 2485775303455 |
15 | 103e003702de4 |
hex | 7811077fc4e3 |
132014535591139 has 2 divisors, whose sum is σ = 132014535591140. Its totient is φ = 132014535591138.
The previous prime is 132014535591089. The next prime is 132014535591163. The reversal of 132014535591139 is 931195535410231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132014535591139 - 213 = 132014535582947 is a prime.
It is not a weakly prime, because it can be changed into another prime (132014535591199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007267795569 + 66007267795570.
It is an arithmetic number, because the mean of its divisors is an integer number (66007267795570).
Almost surely, 2132014535591139 is an apocalyptic number.
132014535591139 is a deficient number, since it is larger than the sum of its proper divisors (1).
132014535591139 is an equidigital number, since it uses as much as digits as its factorization.
132014535591139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2187000, while the sum is 52.
The spelling of 132014535591139 in words is "one hundred thirty-two trillion, fourteen billion, five hundred thirty-five million, five hundred ninety-one thousand, one hundred thirty-nine".
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