132015022032041 has 4 divisors (see below), whose sum is σ = 133183296563412. Its totient is φ = 130846747500672.

The previous prime is 132015022032031. The next prime is 132015022032071. The reversal of 132015022032041 is 140230220510231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2496965672041 + 129518056360000 = 1580179^2 + 11380600^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132015022032041 is a prime.

It is a super-4 number, since 4×132015022032041⁴ (a number of 58 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132015022032041.

It is not an unprimeable number, because it can be changed into a prime (132015022032031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 584137265516 + ... + 584137265741.

It is an arithmetic number, because the mean of its divisors is an integer number (33295824140853).

Almost surely, 2^{132015022032041} is an apocalyptic number.

It is an amenable number.

132015022032041 is a deficient number, since it is larger than the sum of its proper divisors (1168274531371).

132015022032041 is a wasteful number, since it uses less digits than its factorization.

132015022032041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1168274531370.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 132015022032041 its reverse (140230220510231), we get a palindrome (272245242542272).

The spelling of 132015022032041 in words is "one hundred thirty-two trillion, fifteen billion, twenty-two million, thirty-two thousand, forty-one".