Base | Representation |
---|---|
bin | 1100000000011011110011… |
… | …0111000111010100110110 |
3 | 1201202001122102020100201221 |
4 | 3000012330313013110312 |
5 | 3212243340341041032 |
6 | 44024422133540554 |
7 | 2531533013362612 |
oct | 300067467072466 |
9 | 51661572210657 |
10 | 13201603065142 |
11 | 422a84a846518 |
12 | 15926861a475a |
13 | 749ba114453b |
14 | 338d64d98342 |
15 | 17d60d713597 |
hex | c01bcdc7536 |
13201603065142 has 32 divisors (see below), whose sum is σ = 20315467116000. Its totient is φ = 6430261017600.
The previous prime is 13201603065029. The next prime is 13201603065143. The reversal of 13201603065142 is 24156030610231.
13201603065142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13201603065098 and 13201603065107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13201603065143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 469810609 + ... + 469838707.
It is an arithmetic number, because the mean of its divisors is an integer number (634858347375).
Almost surely, 213201603065142 is an apocalyptic number.
13201603065142 is a deficient number, since it is larger than the sum of its proper divisors (7113864050858).
13201603065142 is a wasteful number, since it uses less digits than its factorization.
13201603065142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36432.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 13201603065142 its reverse (24156030610231), we get a palindrome (37357633675373).
The spelling of 13201603065142 in words is "thirteen trillion, two hundred one billion, six hundred three million, sixty-five thousand, one hundred forty-two".
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