Base | Representation |
---|---|
bin | 111101011110011101… |
… | …1010101010111100011 |
3 | 110121202121110022000212 |
4 | 1322330323111113203 |
5 | 4130333241031012 |
6 | 140352030404335 |
7 | 12352355226335 |
oct | 1727473252743 |
9 | 417677408025 |
10 | 132018689507 |
11 | 50a97121471 |
12 | 217049606ab |
13 | c5ac193973 |
14 | 656562b455 |
15 | 367a1b8b22 |
hex | 1ebced55e3 |
132018689507 has 4 divisors (see below), whose sum is σ = 132892985616. Its totient is φ = 131144393400.
The previous prime is 132018689479. The next prime is 132018689519. The reversal of 132018689507 is 705986810231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 705986810231 = 113 ⋅6247670887.
It is a cyclic number.
It is not a de Polignac number, because 132018689507 - 212 = 132018685411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132018689597) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437147828 + ... + 437148129.
It is an arithmetic number, because the mean of its divisors is an integer number (33223246404).
Almost surely, 2132018689507 is an apocalyptic number.
132018689507 is a deficient number, since it is larger than the sum of its proper divisors (874296109).
132018689507 is an equidigital number, since it uses as much as digits as its factorization.
132018689507 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 874296108.
The product of its (nonzero) digits is 725760, while the sum is 50.
The spelling of 132018689507 in words is "one hundred thirty-two billion, eighteen million, six hundred eighty-nine thousand, five hundred seven".
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