Base | Representation |
---|---|
bin | 11110000001001001001101… |
… | …100010001011110101010011 |
3 | 122022102222201011211110010122 |
4 | 132001021031202023311103 |
5 | 114301003432410121233 |
6 | 1144441053035220455 |
7 | 36544062544454432 |
oct | 3601111542136523 |
9 | 568388634743118 |
10 | 132020005551443 |
11 | 3907a4084199a9 |
12 | 129824408a772b |
13 | 58885826b8c59 |
14 | 2485b3397b119 |
15 | 103e223a3bd98 |
hex | 78124d88bd53 |
132020005551443 has 2 divisors, whose sum is σ = 132020005551444. Its totient is φ = 132020005551442.
The previous prime is 132020005551403. The next prime is 132020005551461. The reversal of 132020005551443 is 344155500020231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132020005551443 is a prime.
It is not a weakly prime, because it can be changed into another prime (132020005551403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66010002775721 + 66010002775722.
It is an arithmetic number, because the mean of its divisors is an integer number (66010002775722).
Almost surely, 2132020005551443 is an apocalyptic number.
132020005551443 is a deficient number, since it is larger than the sum of its proper divisors (1).
132020005551443 is an equidigital number, since it uses as much as digits as its factorization.
132020005551443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 132020005551443 its reverse (344155500020231), we get a palindrome (476175505571674).
The spelling of 132020005551443 in words is "one hundred thirty-two trillion, twenty billion, five million, five hundred fifty-one thousand, four hundred forty-three".
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