Search a number
-
+
13202001341297 is a prime number
BaseRepresentation
bin1100000000011101010010…
…0110011010101101110001
31201202002200011122212220122
43000013110212122231301
53212300144320410142
644024525442220025
72531545620564566
oct300072446325561
951662604585818
1013202001341297
11422aa3464426a
121592777654615
13749c358012c2
14338da1c3086d
1517d6336861d2
hexc01d499ab71

13202001341297 has 2 divisors, whose sum is σ = 13202001341298. Its totient is φ = 13202001341296.

The previous prime is 13202001341219. The next prime is 13202001341311. The reversal of 13202001341297 is 79214310020231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12696080680336 + 505920660961 = 3563156^2 + 711281^2 .

It is an emirp because it is prime and its reverse (79214310020231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13202001341297 - 210 = 13202001340273 is a prime.

It is not a weakly prime, because it can be changed into another prime (13202001341897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601000670648 + 6601000670649.

It is an arithmetic number, because the mean of its divisors is an integer number (6601000670649).

Almost surely, 213202001341297 is an apocalyptic number.

It is an amenable number.

13202001341297 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202001341297 is an equidigital number, since it uses as much as digits as its factorization.

13202001341297 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 35.

The spelling of 13202001341297 in words is "thirteen trillion, two hundred two billion, one million, three hundred forty-one thousand, two hundred ninety-seven".