Base | Representation |
---|---|
bin | 11110000001001001011001… |
… | …001100001100000111000001 |
3 | 122022110000012210210221210021 |
4 | 132001021121030030013001 |
5 | 114301004332441041001 |
6 | 1144441124302533441 |
7 | 36544100440632016 |
oct | 3601113114140701 |
9 | 568400183727707 |
10 | 132020201112001 |
11 | 3907a4a884a4a4 |
12 | 12982496297281 |
13 | 58885b407a667 |
14 | 2485b5192570d |
15 | 103e235cbaba1 |
hex | 78125930c1c1 |
132020201112001 has 2 divisors, whose sum is σ = 132020201112002. Its totient is φ = 132020201112000.
The previous prime is 132020201111963. The next prime is 132020201112031. The reversal of 132020201112001 is 100211102020231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128545708840000 + 3474492272001 = 11337800^2 + 1863999^2 .
It is a cyclic number.
It is not a de Polignac number, because 132020201112001 - 215 = 132020201079233 is a prime.
It is not a weakly prime, because it can be changed into another prime (132020201112031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66010100556000 + 66010100556001.
It is an arithmetic number, because the mean of its divisors is an integer number (66010100556001).
Almost surely, 2132020201112001 is an apocalyptic number.
It is an amenable number.
132020201112001 is a deficient number, since it is larger than the sum of its proper divisors (1).
132020201112001 is an equidigital number, since it uses as much as digits as its factorization.
132020201112001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 132020201112001 its reverse (100211102020231), we get a palindrome (232231303132232).
The spelling of 132020201112001 in words is "one hundred thirty-two trillion, twenty billion, two hundred one million, one hundred twelve thousand, one".
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