Base | Representation |
---|---|
bin | 10011001101100010001… |
… | …110110010100011101001 |
3 | 11200012200012212101210122 |
4 | 103031202032302203221 |
5 | 133112233432113022 |
6 | 2450254244053025 |
7 | 164244601244153 |
oct | 23154216624351 |
9 | 4605605771718 |
10 | 1320203004137 |
11 | 4699931a6226 |
12 | 193a45394175 |
13 | 9765786b864 |
14 | 47c807d5ad3 |
15 | 2451c8e0742 |
hex | 133623b28e9 |
1320203004137 has 2 divisors, whose sum is σ = 1320203004138. Its totient is φ = 1320203004136.
The previous prime is 1320203004067. The next prime is 1320203004149. The reversal of 1320203004137 is 7314003020231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1293851650576 + 26351353561 = 1137476^2 + 162331^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320203004137 - 212 = 1320203000041 is a prime.
It is a super-2 number, since 2×13202030041372 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1320203004937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660101502068 + 660101502069.
It is an arithmetic number, because the mean of its divisors is an integer number (660101502069).
Almost surely, 21320203004137 is an apocalyptic number.
It is an amenable number.
1320203004137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320203004137 is an equidigital number, since it uses as much as digits as its factorization.
1320203004137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 26.
Adding to 1320203004137 its reverse (7314003020231), we get a palindrome (8634206024368).
The spelling of 1320203004137 in words is "one trillion, three hundred twenty billion, two hundred three million, four thousand, one hundred thirty-seven".
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