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1320204021121 = 13149572033063
BaseRepresentation
bin10011001101100010010…
…010101010110110000001
311200012200021210001211201
4103031202102222312001
5133112234212133441
62450254321541201
7164244613011136
oct23154222526601
94605607701751
101320204021121
11469993830307
12193a457a4801
1397657b3671b
1447c809bc58d
152451ca41c31
hex133624aad81

1320204021121 has 8 divisors (see below), whose sum is σ = 1330550933184. Its totient is φ = 1309861185360.

The previous prime is 1320204021077. The next prime is 1320204021127. The reversal of 1320204021121 is 1211204020231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1320204021121 - 221 = 1320201923969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1320204021127) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 367165 + ... + 1665898.

It is an arithmetic number, because the mean of its divisors is an integer number (166318866648).

Almost surely, 21320204021121 is an apocalyptic number.

It is an amenable number.

1320204021121 is a deficient number, since it is larger than the sum of its proper divisors (10346912063).

1320204021121 is a wasteful number, since it uses less digits than its factorization.

1320204021121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2038151.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1320204021121 its reverse (1211204020231), we get a palindrome (2531408041352).

The spelling of 1320204021121 in words is "one trillion, three hundred twenty billion, two hundred four million, twenty-one thousand, one hundred twenty-one".

Divisors: 1 131 4957 649367 2033063 266331253 10077893291 1320204021121