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13202134131 = 38353020619
BaseRepresentation
bin11000100101110100…
…01001010001110011
31021002002010220100210
430102322021101303
5204014221243011
610022011315203
7645106200654
oct142272112163
937062126323
1013202134131
11566529585a
12268544bb03
1313252254b4
148d354552b
1552407d6a6
hex312e89473

13202134131 has 8 divisors (see below), whose sum is σ = 17814928320. Its totient is φ = 8695381352.

The previous prime is 13202134129. The next prime is 13202134139. The reversal of 13202134131 is 13143120231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13202134131 - 21 = 13202134129 is a prime.

It is a super-2 number, since 2×132021341312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13202134098 and 13202134107.

It is not an unprimeable number, because it can be changed into a prime (13202134139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26510061 + ... + 26510558.

It is an arithmetic number, because the mean of its divisors is an integer number (2226866040).

Almost surely, 213202134131 is an apocalyptic number.

13202134131 is a deficient number, since it is larger than the sum of its proper divisors (4612794189).

13202134131 is an equidigital number, since it uses as much as digits as its factorization.

13202134131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53020705.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13202134131 its reverse (13143120231), we get a palindrome (26345254362).

The spelling of 13202134131 in words is "thirteen billion, two hundred two million, one hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 3 83 249 53020619 159061857 4400711377 13202134131