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13202134441 = 74317768687
BaseRepresentation
bin11000100101110100…
…01001010110101001
31021002002010220210021
430102322021112221
5204014221300231
610022011320441
7645106201606
oct142272112651
937062126707
1013202134441
115665296011
122685450121
131325225692
148d35456ad
1552407d811
hex312e895a9

13202134441 has 4 divisors (see below), whose sum is σ = 13219903872. Its totient is φ = 13184365012.

The previous prime is 13202134433. The next prime is 13202134447. The reversal of 13202134441 is 14443120231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14443120231 = 43335886517.

It is a cyclic number.

It is not a de Polignac number, because 13202134441 - 23 = 13202134433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13202134447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8883601 + ... + 8885086.

It is an arithmetic number, because the mean of its divisors is an integer number (3304975968).

Almost surely, 213202134441 is an apocalyptic number.

It is an amenable number.

13202134441 is a deficient number, since it is larger than the sum of its proper divisors (17769431).

13202134441 is an equidigital number, since it uses as much as digits as its factorization.

13202134441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17769430.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13202134441 its reverse (14443120231), we get a palindrome (27645254672).

The spelling of 13202134441 in words is "thirteen billion, two hundred two million, one hundred thirty-four thousand, four hundred forty-one".

Divisors: 1 743 17768687 13202134441