Base | Representation |
---|---|
bin | 11000100101110100… |
… | …01010110001010001 |
3 | 1021002002011012202002 |
4 | 30102322022301101 |
5 | 204014221441431 |
6 | 10022011403345 |
7 | 645106224533 |
oct | 142272126121 |
9 | 37062135662 |
10 | 13202140241 |
11 | 566529a404 |
12 | 2685453555 |
13 | 1325228204 |
14 | 8d3547853 |
15 | 5240803cb |
hex | 312e8ac51 |
13202140241 has 4 divisors (see below), whose sum is σ = 13204646400. Its totient is φ = 13199634084.
The previous prime is 13202140229. The next prime is 13202140249. The reversal of 13202140241 is 14204120231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14204120231 = 7 ⋅2029160033.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13202140241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13202140249) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1245161 + ... + 1255718.
It is an arithmetic number, because the mean of its divisors is an integer number (3301161600).
Almost surely, 213202140241 is an apocalyptic number.
It is an amenable number.
13202140241 is a deficient number, since it is larger than the sum of its proper divisors (2506159).
13202140241 is an equidigital number, since it uses as much as digits as its factorization.
13202140241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2506158.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 13202140241 its reverse (14204120231), we get a palindrome (27406260472).
The spelling of 13202140241 in words is "thirteen billion, two hundred two million, one hundred forty thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •