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1320220303107 = 3440073434369
BaseRepresentation
bin10011001101100011010…
…000110001111100000011
311200012201102102021112020
4103031203100301330003
5133112302344144412
62450300102532523
7164245201263366
oct23154320617403
94605642367466
101320220303107
114699a1a411a2
12193a4b137143
139765b317734
1447c82c1a0dd
152451e1ab18c
hex13363431f03

1320220303107 has 4 divisors (see below), whose sum is σ = 1760293737480. Its totient is φ = 880146868736.

The previous prime is 1320220303097. The next prime is 1320220303139. The reversal of 1320220303107 is 7013030220231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1320220303107 - 230 = 1319146561283 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1320220304107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220036717182 + ... + 220036717187.

It is an arithmetic number, because the mean of its divisors is an integer number (440073434370).

Almost surely, 21320220303107 is an apocalyptic number.

1320220303107 is a deficient number, since it is larger than the sum of its proper divisors (440073434373).

1320220303107 is an equidigital number, since it uses as much as digits as its factorization.

1320220303107 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440073434372.

The product of its (nonzero) digits is 1512, while the sum is 24.

Adding to 1320220303107 its reverse (7013030220231), we get a palindrome (8333250523338).

The spelling of 1320220303107 in words is "one trillion, three hundred twenty billion, two hundred twenty million, three hundred three thousand, one hundred seven".

Divisors: 1 3 440073434369 1320220303107