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13202231220553 is a prime number
BaseRepresentation
bin1100000000011110001001…
…0011010101100101001001
31201202010021012012221222011
43000013202103111211021
53212301132143024203
644025004333255521
72531554411535524
oct300074223254511
951663235187864
1013202231220553
114230042384a21
1215928206345a1
13749c7131a62b
14338dc458dbbb
1517d64894376d
hexc01e24d5949

13202231220553 has 2 divisors, whose sum is σ = 13202231220554. Its totient is φ = 13202231220552.

The previous prime is 13202231220533. The next prime is 13202231220593. The reversal of 13202231220553 is 35502213220231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11741258608704 + 1460972611849 = 3426552^2 + 1208707^2 .

It is a cyclic number.

It is not a de Polignac number, because 13202231220553 - 213 = 13202231212361 is a prime.

It is a super-2 number, since 2×132022312205532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13202231220533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601115610276 + 6601115610277.

It is an arithmetic number, because the mean of its divisors is an integer number (6601115610277).

Almost surely, 213202231220553 is an apocalyptic number.

It is an amenable number.

13202231220553 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202231220553 is an equidigital number, since it uses as much as digits as its factorization.

13202231220553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 13202231220553 its reverse (35502213220231), we get a palindrome (48704444440784).

The spelling of 13202231220553 in words is "thirteen trillion, two hundred two billion, two hundred thirty-one million, two hundred twenty thousand, five hundred fifty-three".