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1320231220233 = 3440077073411
BaseRepresentation
bin10011001101100011111…
…010011011010000001001
311200012202011221221000020
4103031203322123100021
5133112313143021413
62450301132531053
7164245363132632
oct23154372332011
94605664857006
101320231220233
114699a8118412
12193a52920a89
139766066a883
1447c8445c889
1524520115c23
hex13363e9b409

1320231220233 has 4 divisors (see below), whose sum is σ = 1760308293648. Its totient is φ = 880154146820.

The previous prime is 1320231220201. The next prime is 1320231220271. The reversal of 1320231220233 is 3320221320231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320231220233 - 25 = 1320231220201 is a prime.

It is a super-2 number, since 2×13202312202332 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1320231220733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220038536703 + ... + 220038536708.

It is an arithmetic number, because the mean of its divisors is an integer number (440077073412).

Almost surely, 21320231220233 is an apocalyptic number.

It is an amenable number.

1320231220233 is a deficient number, since it is larger than the sum of its proper divisors (440077073415).

1320231220233 is an equidigital number, since it uses as much as digits as its factorization.

1320231220233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440077073414.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 1320231220233 its reverse (3320221320231), we get a palindrome (4640452540464).

The spelling of 1320231220233 in words is "one trillion, three hundred twenty billion, two hundred thirty-one million, two hundred twenty thousand, two hundred thirty-three".

Divisors: 1 3 440077073411 1320231220233