Base | Representation |
---|---|
bin | 11000100101110101… |
… | …10110100101101001 |
3 | 1021002002111022221111 |
4 | 30102322312211221 |
5 | 204014243212341 |
6 | 10022015310321 |
7 | 645110603023 |
oct | 142272664551 |
9 | 37062438844 |
10 | 13202319721 |
11 | 5665402238 |
12 | 268551b3a1 |
13 | 132528bb06 |
14 | 8d3593013 |
15 | 5240b8681 |
hex | 312eb6969 |
13202319721 has 2 divisors, whose sum is σ = 13202319722. Its totient is φ = 13202319720.
The previous prime is 13202319701. The next prime is 13202319811. The reversal of 13202319721 is 12791320231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12869768025 + 332551696 = 113445^2 + 18236^2 .
It is an emirp because it is prime and its reverse (12791320231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13202319721 - 29 = 13202319209 is a prime.
It is not a weakly prime, because it can be changed into another prime (13202319701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601159860 + 6601159861.
It is an arithmetic number, because the mean of its divisors is an integer number (6601159861).
Almost surely, 213202319721 is an apocalyptic number.
It is an amenable number.
13202319721 is a deficient number, since it is larger than the sum of its proper divisors (1).
13202319721 is an equidigital number, since it uses as much as digits as its factorization.
13202319721 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 31.
Adding to 13202319721 its reverse (12791320231), we get a palindrome (25993639952).
The spelling of 13202319721 in words is "thirteen billion, two hundred two million, three hundred nineteen thousand, seven hundred twenty-one".
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