Base | Representation |
---|---|
bin | 1100000000011110011110… |
… | …0110000000010011110011 |
3 | 1201202010111101021102210211 |
4 | 3000013213212000103303 |
5 | 3212301322410001433 |
6 | 44025021224204551 |
7 | 2531556540256453 |
oct | 300074746002363 |
9 | 51663441242724 |
10 | 13202320000243 |
11 | 4230088502470 |
12 | 1592846309757 |
13 | 749c86832caa |
14 | 338dd229dd63 |
15 | 17d65162d8cd |
hex | c01e79804f3 |
13202320000243 has 16 divisors (see below), whose sum is σ = 14463929203200. Its totient is φ = 11950951744480.
The previous prime is 13202320000237. The next prime is 13202320000267. The reversal of 13202320000243 is 34200002320231.
It is a cyclic number.
It is not a de Polignac number, because 13202320000243 - 25 = 13202320000211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13202320000843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34414773 + ... + 34796281.
It is an arithmetic number, because the mean of its divisors is an integer number (903995575200).
Almost surely, 213202320000243 is an apocalyptic number.
13202320000243 is a deficient number, since it is larger than the sum of its proper divisors (1261609202957).
13202320000243 is a wasteful number, since it uses less digits than its factorization.
13202320000243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 394922.
The product of its (nonzero) digits is 1728, while the sum is 22.
Adding to 13202320000243 its reverse (34200002320231), we get a palindrome (47402322320474).
The spelling of 13202320000243 in words is "thirteen trillion, two hundred two billion, three hundred twenty million, two hundred forty-three", and thus it is an aban number.
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