Base | Representation |
---|---|
bin | 10011001101100011111… |
… | …110100010111000000001 |
3 | 11200012202020222210012211 |
4 | 103031203332202320001 |
5 | 133112313432100113 |
6 | 2450301212022121 |
7 | 164245405251013 |
oct | 23154376427001 |
9 | 4605666883184 |
10 | 1320232300033 |
11 | 4699a8795709 |
12 | 193a53161941 |
13 | 976609581ca |
14 | 47c846601b3 |
15 | 2452027ab3d |
hex | 13363fa2e01 |
1320232300033 has 2 divisors, whose sum is σ = 1320232300034. Its totient is φ = 1320232300032.
The previous prime is 1320232299983. The next prime is 1320232300067. The reversal of 1320232300033 is 3300032320231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 699277267984 + 620955032049 = 836228^2 + 788007^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320232300033 - 221 = 1320230202881 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1320232299977 and 1320232300013.
It is not a weakly prime, because it can be changed into another prime (1320232300433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660116150016 + 660116150017.
It is an arithmetic number, because the mean of its divisors is an integer number (660116150017).
Almost surely, 21320232300033 is an apocalyptic number.
It is an amenable number.
1320232300033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320232300033 is an equidigital number, since it uses as much as digits as its factorization.
1320232300033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 22.
Adding to 1320232300033 its reverse (3300032320231), we get a palindrome (4620264620264).
The spelling of 1320232300033 in words is "one trillion, three hundred twenty billion, two hundred thirty-two million, three hundred thousand, thirty-three".
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