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13202444033 is a prime number
BaseRepresentation
bin11000100101110110…
…10100111100000001
31021002002201122110122
430102323110330001
5204014311202113
610022022110025
7645111631322
oct142273247401
937062648418
1013202444033
115665487679
12268557b315
13132530357c
148d35c6449
155240e0408
hex312ed4f01

13202444033 has 2 divisors, whose sum is σ = 13202444034. Its totient is φ = 13202444032.

The previous prime is 13202444027. The next prime is 13202444051. The reversal of 13202444033 is 33044420231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8894753344 + 4307690689 = 94312^2 + 65633^2 .

It is a cyclic number.

It is not a de Polignac number, because 13202444033 - 28 = 13202443777 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13202443993 and 13202444011.

It is not a weakly prime, because it can be changed into another prime (13202444093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601222016 + 6601222017.

It is an arithmetic number, because the mean of its divisors is an integer number (6601222017).

Almost surely, 213202444033 is an apocalyptic number.

It is an amenable number.

13202444033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202444033 is an equidigital number, since it uses as much as digits as its factorization.

13202444033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 13202444033 its reverse (33044420231), we get a palindrome (46246864264).

The spelling of 13202444033 in words is "thirteen billion, two hundred two million, four hundred forty-four thousand, thirty-three".