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13203143153 is a prime number
BaseRepresentation
bin11000100101111011…
…11111100111110001
31021002011001011110222
430102331333213301
5204020001040103
610022045102425
7645120602504
oct142275774761
937064034428
1013203143153
115665914962
122685857a15
1313254b9855
148d372913b
155241cc638
hex312f7f9f1

13203143153 has 2 divisors, whose sum is σ = 13203143154. Its totient is φ = 13203143152.

The previous prime is 13203143141. The next prime is 13203143197. The reversal of 13203143153 is 35134130231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9748995169 + 3454147984 = 98737^2 + 58772^2 .

It is a cyclic number.

It is not a de Polignac number, because 13203143153 - 216 = 13203077617 is a prime.

It is a super-2 number, since 2×132031431532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13203143053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601571576 + 6601571577.

It is an arithmetic number, because the mean of its divisors is an integer number (6601571577).

Almost surely, 213203143153 is an apocalyptic number.

It is an amenable number.

13203143153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13203143153 is an equidigital number, since it uses as much as digits as its factorization.

13203143153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 13203143153 its reverse (35134130231), we get a palindrome (48337273384).

The spelling of 13203143153 in words is "thirteen billion, two hundred three million, one hundred forty-three thousand, one hundred fifty-three".