Search a number
-
+
132032012323 is a prime number
BaseRepresentation
bin111101011110110111…
…0001010000000100011
3110121210112112011111111
41322331232022000203
54130400143343243
6140353224124151
712352606405351
oct1727556120043
9417715464444
10132032012323
1150aa36a1062
1221709306657
13c5b1b79aa3
1465672d87d1
15367b44b39d
hex1ebdb8a023

132032012323 has 2 divisors, whose sum is σ = 132032012324. Its totient is φ = 132032012322.

The previous prime is 132032012257. The next prime is 132032012327. The reversal of 132032012323 is 323210230231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132032012323 - 225 = 131998457891 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132032012294 and 132032012303.

It is not a weakly prime, because it can be changed into another prime (132032012327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016006161 + 66016006162.

It is an arithmetic number, because the mean of its divisors is an integer number (66016006162).

Almost surely, 2132032012323 is an apocalyptic number.

132032012323 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032012323 is an equidigital number, since it uses as much as digits as its factorization.

132032012323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 132032012323 its reverse (323210230231), we get a palindrome (455242242554).

The spelling of 132032012323 in words is "one hundred thirty-two billion, thirty-two million, twelve thousand, three hundred twenty-three".