132032025523553 has 4 divisors (see below), whose sum is σ = 132035658702228. Its totient is φ = 132028392344880.

The previous prime is 132032025523457. The next prime is 132032025523571. The reversal of 132032025523553 is 355325520230231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 69049834402129 + 62982191121424 = 8309623^2 + 7936132^2 .

It is a cyclic number.

It is not a de Polignac number, because 132032025523553 - 2¹⁴ = 132032025507169 is a prime.

It is a super-3 number, since 3×132032025523553³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132032025523553.

It is not an unprimeable number, because it can be changed into a prime (132032025526553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1816534826 + ... + 1816607507.

It is an arithmetic number, because the mean of its divisors is an integer number (33008914675557).

Almost surely, 2^{132032025523553} is an apocalyptic number.

It is an amenable number.

132032025523553 is a deficient number, since it is larger than the sum of its proper divisors (3633178675).

132032025523553 is an equidigital number, since it uses as much as digits as its factorization.

132032025523553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3633178674.

The product of its (nonzero) digits is 810000, while the sum is 41.

Adding to 132032025523553 its reverse (355325520230231), we get a palindrome (487357545753784).

The spelling of 132032025523553 in words is "one hundred thirty-two trillion, thirty-two billion, twenty-five million, five hundred twenty-three thousand, five hundred fifty-three".