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132032140441 = 2919123836819
BaseRepresentation
bin111101011110110111…
…0101001010010011001
3110121210112202200020121
41322331232221102121
54130400211443231
6140353230553241
712352610451025
oct1727556512231
9417715680217
10132032140441
1150aa3779343
1221709368821
13c5b1bc31b6
14656732d385
15367b474311
hex1ebdba9499

132032140441 has 8 divisors (see below), whose sum is σ = 137300083200. Its totient is φ = 126811871760.

The previous prime is 132032140411. The next prime is 132032140447. The reversal of 132032140441 is 144041230231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132032140441 - 225 = 131998586009 is a prime.

It is a super-2 number, since 2×1320321404412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132032140447) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11912871 + ... + 11923948.

It is an arithmetic number, because the mean of its divisors is an integer number (17162510400).

Almost surely, 2132032140441 is an apocalyptic number.

It is an amenable number.

132032140441 is a deficient number, since it is larger than the sum of its proper divisors (5267942759).

132032140441 is a wasteful number, since it uses less digits than its factorization.

132032140441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23837039.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 132032140441 its reverse (144041230231), we get a palindrome (276073370672).

The spelling of 132032140441 in words is "one hundred thirty-two billion, thirty-two million, one hundred forty thousand, four hundred forty-one".

Divisors: 1 29 191 5539 23836819 691267751 4552832429 132032140441