1320322001113 has 4 divisors (see below), whose sum is σ = 1320330696448. Its totient is φ = 1320313305780.

The previous prime is 1320322001111. The next prime is 1320322001149. The reversal of 1320322001113 is 3111002230231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320322001113 - 2¹ = 1320322001111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1320322001111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4115781 + ... + 4424962.

It is an arithmetic number, because the mean of its divisors is an integer number (330082674112).

Almost surely, 2^{1320322001113} is an apocalyptic number.

It is an amenable number.

1320322001113 is a deficient number, since it is larger than the sum of its proper divisors (8695335).

1320322001113 is an equidigital number, since it uses as much as digits as its factorization.

1320322001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8695334.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1320322001113 its reverse (3111002230231), we get a palindrome (4431324231344).

It can be divided in two parts, 132032 and 2001113, that added together give a triangular number (2133145 = T₂₀₆₅).

The spelling of 1320322001113 in words is "one trillion, three hundred twenty billion, three hundred twenty-two million, one thousand, one hundred thirteen".