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1320322421123 is a prime number
BaseRepresentation
bin10011001101101001010…
…110010101000110000011
311200012222112120102002222
4103031221112111012003
5133113010014433443
62450314151401255
7164250551256506
oct23155126250603
94605875512088
101320322421123
11469a44649a52
12193a7938322b
13976765202b4
1447c925dd13d
152452812d468
hex13369595183

1320322421123 has 2 divisors, whose sum is σ = 1320322421124. Its totient is φ = 1320322421122.

The previous prime is 1320322421101. The next prime is 1320322421207. The reversal of 1320322421123 is 3211242230231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1320322421123 - 218 = 1320322158979 is a prime.

It is a super-2 number, since 2×13203224211232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1320322421092 and 1320322421101.

It is not a weakly prime, because it can be changed into another prime (1320322421323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660161210561 + 660161210562.

It is an arithmetic number, because the mean of its divisors is an integer number (660161210562).

Almost surely, 21320322421123 is an apocalyptic number.

1320322421123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320322421123 is an equidigital number, since it uses as much as digits as its factorization.

1320322421123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 1320322421123 its reverse (3211242230231), we get a palindrome (4531564651354).

The spelling of 1320322421123 in words is "one trillion, three hundred twenty billion, three hundred twenty-two million, four hundred twenty-one thousand, one hundred twenty-three".