Base | Representation |
---|---|
bin | 11110000001010100111000… |
… | …111010100011110010001001 |
3 | 122022111012002001010010012121 |
4 | 132001110320322203302021 |
5 | 114301210122344140403 |
6 | 1144450525201011241 |
7 | 36545015352113140 |
oct | 3601247072436211 |
9 | 568435061103177 |
10 | 132032544521353 |
11 | 39084762334653 |
12 | 12984960023b21 |
13 | 58898003cb588 |
14 | 24865a2db6757 |
15 | 103e7097723bd |
hex | 781538ea3c89 |
132032544521353 has 16 divisors (see below), whose sum is σ = 154886509486080. Its totient is φ = 110213360568000.
The previous prime is 132032544521347. The next prime is 132032544521387. The reversal of 132032544521353 is 353125445230231.
It is a cyclic number.
It is not a de Polignac number, because 132032544521353 - 29 = 132032544520841 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132032544521453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1530697993 + ... + 1530784246.
It is an arithmetic number, because the mean of its divisors is an integer number (9680406842880).
Almost surely, 2132032544521353 is an apocalyptic number.
It is an amenable number.
132032544521353 is a deficient number, since it is larger than the sum of its proper divisors (22853964964727).
132032544521353 is a wasteful number, since it uses less digits than its factorization.
132032544521353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3061482408.
The product of its (nonzero) digits is 1296000, while the sum is 43.
Adding to 132032544521353 its reverse (353125445230231), we get a palindrome (485157989751584).
The spelling of 132032544521353 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred forty-four million, five hundred twenty-one thousand, three hundred fifty-three".
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