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132033511531052 = 22197167555217679
BaseRepresentation
bin11110000001010101110010…
…100011011010001000101100
3122022111021120102201022010122
4132001111302203122020230
5114301214112422443202
61144451205143224112
736545051333422325
oct3601256243321054
9568437512638118
10132033511531052
113908510917531a
1212984b8ba48038
135889925857671
1424866555b744c
15103e7645d89a2
hex7815728da22c

132033511531052 has 12 divisors (see below), whose sum is σ = 232231531704480. Its totient is φ = 65681645329776.

The previous prime is 132033511531039. The next prime is 132033511531057. The reversal of 132033511531052 is 250135115330231.

It is a super-4 number, since 4×1320335115310524 (a number of 58 digits) contains 4444 as substring.

It is not an unprimeable number, because it can be changed into a prime (132033511531057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83777608052 + ... + 83777609627.

It is an arithmetic number, because the mean of its divisors is an integer number (19352627642040).

Almost surely, 2132033511531052 is an apocalyptic number.

It is an amenable number.

132033511531052 is a deficient number, since it is larger than the sum of its proper divisors (100198020173428).

132033511531052 is a wasteful number, since it uses less digits than its factorization.

132033511531052 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167555217880 (or 167555217878 counting only the distinct ones).

The product of its (nonzero) digits is 40500, while the sum is 35.

Adding to 132033511531052 its reverse (250135115330231), we get a palindrome (382168626861283).

The spelling of 132033511531052 in words is "one hundred thirty-two trillion, thirty-three billion, five hundred eleven million, five hundred thirty-one thousand, fifty-two".

Divisors: 1 2 4 197 394 788 167555217679 335110435358 670220870716 33008377882763 66016755765526 132033511531052