Base | Representation |
---|---|
bin | 11110000001010101110010… |
… | …100011011010001000101100 |
3 | 122022111021120102201022010122 |
4 | 132001111302203122020230 |
5 | 114301214112422443202 |
6 | 1144451205143224112 |
7 | 36545051333422325 |
oct | 3601256243321054 |
9 | 568437512638118 |
10 | 132033511531052 |
11 | 3908510917531a |
12 | 12984b8ba48038 |
13 | 5889925857671 |
14 | 24866555b744c |
15 | 103e7645d89a2 |
hex | 7815728da22c |
132033511531052 has 12 divisors (see below), whose sum is σ = 232231531704480. Its totient is φ = 65681645329776.
The previous prime is 132033511531039. The next prime is 132033511531057. The reversal of 132033511531052 is 250135115330231.
It is a super-4 number, since 4×1320335115310524 (a number of 58 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (132033511531057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83777608052 + ... + 83777609627.
It is an arithmetic number, because the mean of its divisors is an integer number (19352627642040).
Almost surely, 2132033511531052 is an apocalyptic number.
It is an amenable number.
132033511531052 is a deficient number, since it is larger than the sum of its proper divisors (100198020173428).
132033511531052 is a wasteful number, since it uses less digits than its factorization.
132033511531052 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167555217880 (or 167555217878 counting only the distinct ones).
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 132033511531052 its reverse (250135115330231), we get a palindrome (382168626861283).
The spelling of 132033511531052 in words is "one hundred thirty-two trillion, thirty-three billion, five hundred eleven million, five hundred thirty-one thousand, fifty-two".
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