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132040110134355 = 3511637568937239
BaseRepresentation
bin11110000001011011111011…
…110111000101010001010011
3122022111220121022011002011120
4132001123323313011101103
5114301321121143244410
61144454220022213323
736545404006551663
oct3601337367052123
9568456538132146
10132040110134355
113908799498a685
1212986311884243
13588a437950367
142486abdac81a3
15103e9eda65570
hex7816fbdc5453

132040110134355 has 16 divisors (see below), whose sum is σ = 211445830736640. Its totient is φ = 70360840564448.

The previous prime is 132040110134347. The next prime is 132040110134453. The reversal of 132040110134355 is 553431011040231.

It is a cyclic number.

It is not a de Polignac number, because 132040110134355 - 23 = 132040110134347 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3784451175 + ... + 3784486064.

It is an arithmetic number, because the mean of its divisors is an integer number (13215364421040).

Almost surely, 2132040110134355 is an apocalyptic number.

132040110134355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

132040110134355 is a deficient number, since it is larger than the sum of its proper divisors (79405720602285).

132040110134355 is a wasteful number, since it uses less digits than its factorization.

132040110134355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7568938410.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 132040110134355 its reverse (553431011040231), we get a palindrome (685471121174586).

The spelling of 132040110134355 in words is "one hundred thirty-two trillion, forty billion, one hundred ten million, one hundred thirty-four thousand, three hundred fifty-five".

Divisors: 1 3 5 15 1163 3489 5815 17445 7568937239 22706811717 37844686195 113534058585 8802674008957 26408022026871 44013370044785 132040110134355