Base | Representation |
---|---|
bin | 11110000001011100000001… |
… | …011101100010011100111010 |
3 | 122022111220211211222002202202 |
4 | 132001130001131202130322 |
5 | 114301321314222221214 |
6 | 1144454233220230202 |
7 | 36545406230346326 |
oct | 3601340135423472 |
9 | 568456754862682 |
10 | 132040204101434 |
11 | 39087a32a30522 |
12 | 1298633923b362 |
13 | 588a451260b95 |
14 | 2486acc388986 |
15 | 103ea06e276de |
hex | 78170176273a |
132040204101434 has 8 divisors (see below), whose sum is σ = 198062685019008. Its totient is φ = 66019309095100.
The previous prime is 132040204101397. The next prime is 132040204101451. The reversal of 132040204101434 is 434101402040231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 132040204101397 and 132040204101406.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 396269642 + ... + 396602709.
It is an arithmetic number, because the mean of its divisors is an integer number (24757835627376).
Almost surely, 2132040204101434 is an apocalyptic number.
132040204101434 is a deficient number, since it is larger than the sum of its proper divisors (66022480917574).
132040204101434 is an equidigital number, since it uses as much as digits as its factorization.
132040204101434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 792955620.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 132040204101434 its reverse (434101402040231), we get a palindrome (566141606141665).
The spelling of 132040204101434 in words is "one hundred thirty-two trillion, forty billion, two hundred four million, one hundred one thousand, four hundred thirty-four".
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