Base | Representation |
---|---|
bin | 11000100110000010… |
… | …11001010110111011 |
3 | 1021002012201110212110 |
4 | 30103001121112323 |
5 | 204020213110003 |
6 | 10022120143403 |
7 | 645131305605 |
oct | 142301312673 |
9 | 37065643773 |
10 | 13204035003 |
11 | 5666373a25 |
12 | 2686007b63 |
13 | 132573c783 |
14 | 8d38bc175 |
15 | 524306a03 |
hex | 3130595bb |
13204035003 has 16 divisors (see below), whose sum is σ = 18188384256. Its totient is φ = 8511659520.
The previous prime is 13204035001. The next prime is 13204035011. The reversal of 13204035003 is 30053040231.
13204035003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13204035003 - 21 = 13204035001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13204035001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54850 + ... + 171512.
It is an arithmetic number, because the mean of its divisors is an integer number (1136774016).
Almost surely, 213204035003 is an apocalyptic number.
13204035003 is a deficient number, since it is larger than the sum of its proper divisors (4984349253).
13204035003 is a wasteful number, since it uses less digits than its factorization.
13204035003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 117914.
The product of its (nonzero) digits is 1080, while the sum is 21.
Adding to 13204035003 its reverse (30053040231), we get a palindrome (43257075234).
The spelling of 13204035003 in words is "thirteen billion, two hundred four million, thirty-five thousand, three".
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